How Do You Calculate the Acceleration of a Weight and Tension in a Yo-Yo System?

  • Thread starter Thread starter lehel
  • Start date Start date
  • Tags Tags
    Rolling Weight
AI Thread Summary
To calculate the acceleration of an 8lb block and the tension in a yo-yo system, the problem involves a 16lb yo-yo with specific dimensions and a cord configuration. The equations of motion include F = ma and torque = I*alpha, with the moment of inertia calculated using the radius of gyration. The user initially struggles with four unknowns and three equations but realizes the need for a relationship between the accelerations of the weight and the yo-yo. The correct relationship is established as a-weight = a-yo-yo - R*alpha, allowing for the calculation of the desired values. Ultimately, the acceleration of the block is found to be 4.830 ft/s² and the tension in the cord is 6.792 lb.
lehel
Messages
15
Reaction score
0

Homework Statement


a 16lb yo-yo is resting on a horizontal table and is free to roll. The dimensions are r = 4in and R = 12in and the radius of gyration about the CM is 6in. A cord is wrapped around the inner radius, the passes over a perfect pulley, and is attached to a 8lb block.

Find acceleration of 8lb block and the tension in the cord

(answers are 4.830ft/s^2 and 6.792lb)

Homework Equations



F = ma
torque = I*alpha = F*moment-arm
Iaxis = Icm + mh^2
I = (radius-gyration)R^2




The Attempt at a Solution



there are two accelerations a1 (weight) and a2 (yo-yo).

(16/32slugs)*a2 = T

I at table contact point = 90slug*in^2

net torqe at table contact point = 90slug*in^2 * alpha = T(12in - 4in)

T = 11.25*alpha and 0.5slugs * a2 = T

for weight, (8/32slugs)a1 = 8lb - T

so far, I have 4 unknowns and 3 equations so I can't solve for anything. What equation am I missing? i don't know how to find a relationship between alpha and a2 (i thought a2 = 12in*alpha but that doesn't work out right).

thanks in advance
 
Physics news on Phys.org
Consider pure rotation about axis passes through contact point. the center of mass is 12 in from contact point.
 
i found out what i was missing: an equation describing the relationship between the acceleration of the weight and the accleration of the yo-yo.

a-weight = a-yo-yo - R*alpha.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top