How Do You Calculate the Angle of Inclination for a Slide?

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To calculate the angle of inclination for the slide, the relationship between the tangent of the angle and the heights of the two points must be used. The heights measured are 23 cm and 35 cm, resulting in a vertical difference of 12 cm. The horizontal distance between the two points is 1 meter. By applying the tangent function, the angle can be found using the formula tan(θ) = opposite/adjacent, where the opposite side is 0.12 m (12 cm) and the adjacent side is 1 m. The angle of inclination can then be determined using the inverse tangent function.
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Homework Statement

/ attempt

I have to find the angel of inclination. I have a slide forming a triangle. We measured two points in the slide a meter apart. those two points are 23cm in one point and 35cm in another. All together it has a height for 58cm. However, I have no clue how to find the angle of inclination. I know I should use either sin or tan but I don't know how I plug in the values

Attached is a picture.

much thanks,

Chronie

http://img295.imageshack.us/img295/782/49775363zx5.th.jpg
 
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chronie said:

Homework Statement

/ attempt

I have to find the angel of inclination. I have a slide forming a triangle. We measured two points in the slide a meter apart. those two points are 23cm in one point and 35cm in another. All together it has a height for 58cm. However, I have no clue how to find the angle of inclination. I know I should use either sin or tan but I don't know how I plug in the value.

It is not too clear from the picture, but are the two lengths 23 cm and 35 cm elevations of points on the slide above the horizontal, and the two points are 1 m apart as measured along the horizontal?

Think about the relationship between tan \theta_i, where \theta_i is the angle of inclination, and the legs of triangles with heights of 23 and 35 cm. If the 23 cm leg is at distance x from the vertex, i.e. where the slide intersects with the horizontal (ground, or reference plane), what is the distance to the 35 cm leg.

Think of similar triangles sharing a common horizontal base, vertex and hypotenuse.
 
So I should take the difference of distance between the two positions.

That gets me 12. Should I then make a triangle and use .12m as my hypotenuse and 1m as my other side and just take the tan inverse of that?
 
chronie said:
So I should take the difference of distance between the two positions.

That gets me 12 cm. Should I then make a triangle and use .12 m as my hypotenuse and 1m as my other side and just take the tan inverse of that?
Well, the 0.12 m would be the vertical leg and 1 m would be the other leg, but if one finds the tan-1 of the ratio (0.12/1), that would give the angle of inclination.
 
ok thank you Astronuc,

I'm new to my college physics classes and some easy things stump me!SOLVED
 
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