How Do You Calculate the Center of Mass for a Plate with a Circular Hole?

AI Thread Summary
To calculate the center of mass (CM) of a rectangular plate with a circular hole, first determine the mass and position vectors of both the plate and the hole. The mass of the plate is calculated using its area and uniform density, while the mass of the hole is derived similarly. The position vectors for the CM of the plate and the hole are established, allowing for the application of the formula R = (M*R1 - m*R2)/(M - m) to find the CM of the remaining structure. This method effectively accounts for the mass removed by the hole. Understanding these calculations is essential for accurately determining the CM of the modified plate.
heloudan
Messages
2
Reaction score
0
A thin rectangular plate of uniform areal density σ = 3.13 kg/m2 has length of 44.0 cm and width of 26.0 cm. The lower left hand corner is located at the origin, (x,y)= (0,0) and the length is along the x-axis.
There is a circular hole of radius 7.00 cm with center at (x,y) = (16.00,11.00) cm in the plate

Calculate the x-coordinate of CM of the plate.!?
Calculate the distance of the plate's CM from the origin.!?



for some odd reason i can figure out any other problem but this one if someone could help me out that would be great
 
Physics news on Phys.org
do you have to calculate it?
you can hang it from two or more points to find the CM :-)
 
yes i have to calculate it i don't even know where to start
 
Find the position vectors of the CM of rectangular plate and removed circular disc.
Let M be the mass of plate and m be the mass of the disc.
Position vector R1 of M = (022i + 0.13j). Mass M = σ*A. where A is the area of the plate
Position vector R2 of m = (0.16i + 0.11j) Mass n = σ*a ,where a is the area of the removed circular disc.
Then the position vector of CM of the remaining mass of the rectangular plate is
R = (M*R1 - m*R2)/(M - m)
 
If you know the moment of inertia at any two points, can you use the principal axis theorem to triangulate the CM?
Bob S
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top