How Do You Calculate the Electric Field Ex at a Point in a Voltage Field?

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To calculate the electric field Ex at the point (2,1) from the given potential function V(x,y) = 20x^4 + 60y^3, use the formula Ex = -∂V/∂x. The partial derivative with respect to x yields Ex = -80x^3. At x = 2, substituting this value gives Ex = -640. The y component does not affect Ex in this case, as the partial derivative with respect to x eliminates the y terms.
wiiman3893
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Here is the problem:

Given that electric potential is given as a function of x and y: V(x,y)=20x4 + 60y3

What is Ex at (2,1)?

I have tried using E=-DV/DV, but I keep getting confused on how to derive this as it's been a while since I took calculus. I am also unsure of how to plug in the number, like if I only derive the x component and only plug the x into it, or if the y component is involved.
 
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Use the -gradient.
 
And how would I do that?
 
What's the formula for finding the gradient of a function in rectangular coordinates?
 
If using the gradient, just take the partial derivatives. One with respect to x, the other with respect to y.

If I understand the question right, you want to just take the partial derivative with respect to x to get Ex. That's 80x^3. The y term completely disappears.

In this particular example when you take the partial with respect to x, all of the y terms disappear. That doesn't always happen. So all you would have is plug in the 2 for x.
 
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