How Do You Calculate the Electric Force Between Charges in Physics?

AI Thread Summary
To calculate the electric force between charges in physics, use Coulomb's law, F = kQ1Q2/r^2, where k is the electrostatic constant. The distance between charges is determined using the Pythagorean theorem. In the discussion, a user initially miscalculated the proportionality constant k, which should be 8.9 x 10^9 instead of 8.9 x 10^29. Additionally, when determining the x-component of the force, it's crucial to use the correct charge values and understand the direction of the force, as negative results indicate direction rather than magnitude. Accurate calculations and understanding of vector components are essential for solving these problems correctly.
GreyGus
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Homework Statement



Three positive charges are located in the x-y plane (see plot below), with Q1=3.10 μC, Q2=5.20 μC and Q3=6.30 μC. Note that the charges are located at grid intersections, and that the x and y coordinates are in cm.
dynamically generated plot
A. Calculate the magnitude of the electric force on Q1 due to Q2.


Homework Equations


F=kq1q2/r^2



The Attempt at a Solution


Fx=k(3.1*10^-6)(5.2*10^-6)/((4/100)^2)
Fy=k(3.1*10^-6)(5.2*10^-6)/((3/100)^2)
Then for the magnitude: sqrt((160.977)^2+(90.54)^2))
Thank you in advance because I really cannot figure out what I'm doing wrong.
 

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Dear GreyGus;
The solution is just as simple as two steps:
1- Calculate the distance between the two charges using Pythagoras theory (i.e. r = sqrt((the x component of distance)^2 + (the y component of distance)^2)).
2- Calculate the electeric force exerted on Q1 by Q2 using coloumb's law
(F= kQ1Q2/r^2). and hen proceed.

I hope this answers your question.
 
Thank you very much. I appreciate it.
 
ok so I did
x=.04 m
y=.03m
3.10 uC=.000003 C
5.20 uC=.0000052 C
r=sqrt((.04^2)+(.03^2))=.05
F=(9*10^29)(.000003)(.000005)/(.05^2)=5.803e21 N but that's wrong. What am I doing wrong now?
 
The error would be with the proportionality constant k, it's (8.9*10^9) not (8.9*10^29).
I hope this makes sense
 
Oh I see, Thank you very much for your help.
 
How would you find the x-component of force q1 to q3? I have tried:
r=.1
f=k(3.1*10^-6)(5.2*10^-6)/(.1^2)
tantheta=(.06/.08)=36.9
x-component=11.61 N. But that's not right. What did I do wrong on this one?
 
GreyGus said:
How would you find the x-component of force q1 to q3? I have tried:
r=.1
f=k(3.1*10^-6)(5.2*10^-6)/(.1^2)
tantheta=(.06/.08)=36.9
x-component=11.61 N. But that's not right. What did I do wrong on this one?
Make sure you're using the right charge.
 
  • #10
Oh my bad. Ok so I got the answer, but I want to know why is the answer negative?
 
  • #11
GreyGus said:
Oh my bad. Ok so I got the answer, but I want to know why is the answer negative?
The x-component of the force on q3 should not be negative.
 
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