How Do You Calculate the Empirical Formula for Nitrogen and Oxygen Compositions?

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To calculate the empirical formula for nitrogen and oxygen compositions, start by determining the mass of each element based on the given percentages. For a 100g sample, 36.8g of nitrogen and 63.25g of oxygen can be derived from the first set of percentages, while the second set yields 63.6g of nitrogen and 36.4g of oxygen. Next, convert these masses to moles using the atomic weights of nitrogen (14) and oxygen (16). The mole ratio will then provide the empirical formula. It is essential to show your work to receive further assistance in solving these calculations.
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1. 36.8% of N and 63.25% of O
2.63.6% of N and 36.4% of O
at wts: N=14 and O=16



answer it thanks!
 
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donniemsb_12 said:
1. 36.8% of N and 63.25% of O
2.63.6% of N and 36.4% of O
at wts: N=14 and O=16



answer it thanks!

Imagine, for instance 100g of sample 1. What mass is N, what mass is O? How many moles of each?
 
i don't know . that's the given of our teacher :(
 
If I had 100 metres of string, and 54% was black, 46% white, how much would be black and how much white?
 
what ? :))
 
Do you know what % means?
 
donniemsb_12 said:
1. 36.8% of N and 63.25% of O
2.63.6% of N and 36.4% of O
at wts: N=14 and O=16



answer it thanks!

Welcome to the PF.

This is schoolwork, so I've moved it to the Homework Help forums, per the PF Rules. Also part of the rules is that you mush show us your work, before we can be of help. We do not do your schoolwork for you.

Please show us your work toward a solution...
 
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