How do you calculate the exit velocity in aerodynamics?

AI Thread Summary
To calculate the exit velocity in aerodynamics, use the principle of conservation of mass, which states that the volumetric flow rate must remain constant. Given an inlet area of 23 ft² and an inlet velocity of 107 ft/sec, the equation for volumetric flow can be set up as (inlet velocity) x (inlet area) = (exit velocity) x (exit area). By substituting the known values, the equation becomes 107 x 23 = (exit velocity) x 12. Solving for exit velocity yields 205 ft/s. The flow is considered incompressible since the Mach number is less than 0.3.
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Homework Statement



Given: Inlet area = 23 ft², Inlet velocity = 107 ft/sec, Exit area = 12 ft². Find exit velocity

The Attempt at a Solution



I am having a hard time solving this. Can someone explain how to do this? Thanks
 
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Mach number = 107/1116 = 0.0959
This is less than 0.3 so the flow is incompressible

(volumetric flow)in = (volumetric flow)out
(velocity)in x (Cross-sectional Area)in = (velocity)out x (Cross-sectional Area)out
107 x 23 = (velocity)out x 12
(velocity)out = 205 ft/s
 
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