How Do You Calculate the Force Needed to Move a Block Up an Inclined Surface?

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To calculate the force needed to move a 150N block up a 20-degree inclined surface with a friction coefficient of 0.27, the normal force (N) must be determined, as it is not equal to the weight due to the incline. The frictional force can be calculated using the equation F = μN, where μ is the coefficient of friction. A free body diagram is recommended to analyze the forces acting on the block and derive the correct normal force. The applied horizontal force must overcome both the friction and the component of the weight acting down the slope. Understanding these mechanics is crucial for solving the problem accurately.
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Hi, I am working on this question its part of a larger question about dynamic viscosity in thermofluids but its the basic mechanics of friction I forget how to do

Homework Statement



A block weighing 150N is to be moved at constant velocity 0.8m/s up an inclined surface with a friction coefficient of 0.27. Determine the force F that needs to be applied in the horizontal direction.

(the elevation of the slope is 20 degrees)

Homework Equations



F = μN (i think)

The Attempt at a Solution



Applying the basic equation to find the horizontal force results in F = μN,
0.27 X 150 = 40.5N the force required to overcome the friction move the block (Im not sure if the velocity is required for this part but i mentioned it in case it was)
 
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Because the surface is at an angle, N is not simply equal to the weight, 150 N.

You can get N by drawing a free body diagram showing all forces on the block, and writing separate equations for the horizontal and vertical force components.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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