How Do You Calculate the Force on a Ferris Wheel Rider at a Specific Point?

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To calculate the total force on a Ferris wheel rider at a specific point, it's essential to consider both the gravitational force and the centripetal force acting on the rider. At one quarter revolution past the highest point, the direction of the forces changes, requiring a diagram for clarity. The rider's mass is 42 kg, and the Ferris wheel has a radius of 25 m, with a rotation period of 20 seconds. Understanding the relationship between speed and force is crucial, leading to the creation of a graph that illustrates the force as a function of the Ferris wheel's period. Properly visualizing these forces will aid in accurately calculating the total force experienced by the rider.
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Just before finals you decide to visit an amusement park set up in the Metrodome. Since it is a weekend, you invite your favorite niece along. She loves to ride on a Ferris wheel, and there is one at the amusement park. The Ferris wheel has seats on the rim of a circle with a radius of 25 m. The Ferris wheel rotates at a constant speed and makes one complete revolution every 20 seconds. While you wait, your niece who has a mass of 42 kg, rides the Ferris wheel. [B]To kill time you decide to calculate the total force (both magnitude and direction) on her when she is one quarter revolution past the highest point. [/B]Because the Ferris wheel can be run at different speeds, you also decide to make a graph which gives the magnitude of the force on her at that point as a function of the period of the Ferris wheel.

please help me..Of course I know circular motion,centripetal acceleration etc..but I can't understand this bold part.
 
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The bold part just specifies the location of the person at the moment of interest. You need that to specify the direction of the force on her. (Draw yourself a diagram.)
 
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