How Do You Calculate the Frequency and Maximum Velocity of a Mass on a Spring?

AI Thread Summary
To calculate the frequency and maximum velocity of a mass on a spring, the spring's extension and displacement are crucial. The equilibrium position is established at 25mm, with an additional displacement of 20mm leading to a measured displacement of 19.2mm at 0.05 seconds. The angular frequency (w) can be calculated using the formula w=sqrt(k/m), where k is the spring constant and m is the mass. Although the spring constant (k) is not provided, it can be derived from the force (F) and displacement (x) using k = F/x. Understanding these relationships allows for the calculation of the period (T) without needing the specific values of k or m.
Kev1n
Messages
38
Reaction score
0
1. A mass attached to the lower end of a vertical spring causes the spring to extend 25mm to its equilibrium position. The mass is then displaced a further 20mm and released. A trace of the vibration and time measurements are taken. From these measurements it can be seen that the displacement from equilibrium position is 19.2 when the time is 0.05s
A. Calculate the expected frequeny of vibration, B. Calculate the maximm velocity of the mass. I have struggled here as ther is no (k) for the spring or mass
It would be appreciated if anyone could havea look over at my attempt and comment, thanks




2. w=sqrt(k/m), mg=kl, m=kl/g



3. A. w=sqrt (k/m), l = 25mm so 0.25m, g =9.81
m = l/g = 0.025
Basically now can see where to go without k
 
Physics news on Phys.org
To find the period of a spring you do not need to know the mass or the spring constant.

Substitute the calculation for the spring constant into the equation for the period, you should find that you are left with only variables you are able to calculate.

T = 2\pi\sqrt{\frac{k}{m}}

k = \frac{F}{x}

And think about the calculation for F.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top