How Do You Calculate the Gravitational Acceleration of a Satellite in Orbit?

Meroko
Messages
1
Reaction score
0

Homework Statement


Synchronous communications satellites are placed in a circular orbit that is 3.59 X 10^7m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?


Homework Equations


F=G M1M2 / R^2/ mp
g= GMe / r^2
r= Re + H
w=mg
g=w/m

The Attempt at a Solution


I tried to put the numbers in the "g= GMe / r^2" equation, which turns out to be
g= 6.673 X 10^-11 X 5.9742 X 10^24 /( 3.59 X 10^7)^2

But the answer that I got is wrong. Can someone please help me fix my mistakes and help me get the right answer?
 
Physics news on Phys.org
Consider the third equation in your list of relevant equations.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top