Calculating Third Maximum in Single Slit Illuminated by He-Ne Laser

[AClass]

Homework Statement

A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees

Homework Equations

Sin Theta(m) = (m + 0.5) Lambda/w

The Attempt at a Solution

Sin Theta(3) = (3 + 0.5)(633 x 10x9)/2.2 x 10^5
=(3.5)(633 x 10 e-9)/2.2 x 10 e-5
=0.1

Theta = 5.8 degrees

The position of the third maximum in degrees is 5.8 degrees.

Could someone verify my answer please?

 

[anathema]

I can confirm that your solution is correct. The equation you used is the correct formula for calculating the position of the mth maximum in a single slit diffraction pattern. Good job!