How Do You Calculate the Volume of NaOH Needed to Neutralize an Acidic Solution?

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To calculate the volume of NaOH needed to neutralize a 400m³ solution with a pH of 2, one must first determine the hydrogen ion concentration using the formula 10^-(pH). Assuming the solution is a strong acid simplifies the calculation, allowing the mole of H+ to be balanced with the mole of OH- needed for neutralization. The heat of neutralization is noted as -55.9 kJ/mol, and the energy balance equation is discussed, focusing on the mass used for calculations. Confusion arises regarding which mass to use for the energy calculations, particularly whether to use the mass of water produced or the total mass of reactants. The final temperature calculated appears excessively high, prompting a need for clarification on the methodology used.
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can some one help me withe this?
i want to neutralise a 400m3 of unknown solutions in pH 2 with sodium hydroxide. homework can i calculate the volume of alkaline needed? please help me!
 
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HINT: Knowing the pH you can determine the hydrogen ion concentration.
 
I hate such questions. You can't calculate anything without assuming that you have a solution of strong acid. Then (and only then) Hootenanny hint will work.
 
Thank you

Thank you! I solve it already by assuming it's a strong acid and got the answer. Thank you!
 
Borek said:
I hate such questions. You can't calculate anything without assuming that you have a solution of strong acid. Then (and only then) Hootenanny hint will work.


Borek

Ahh, yes thank you Borek. I had forgotten about week acids (never liked them anyway ) As Borek said, I think one would have to assume that the acid in question is a strong acid as no dissociation constant is given.
 
Problems Again

I solved for the heat of neutralization already, I thought, but now, I got the final temperature after reaction is 121.75 oC which I think is too big.

I start with initial pH = 2 and final the conc H+ = 10^-(pH=2) then I find the mole by multipling the conc with the tank volume (400m3), the I find the mass by multiply it with MW.

To neutralise 1 mole of H+, I need 1 mole of OH-, so I balance the mole of OH- needed with the mole of H+ I calculated justnow. The I got the mass and volume of NaOH needed to neutralize the pH 2.

The heat of neutralization is -55.9 kJ/mol. The energy balance is (m.Cp.del_T)in = (m.del_H) + (m.Cp.del_T)out

But since i use the initial temperature and reference temperature both also 25 oC, so the (m.Cp.del_T)in is cancelled. What left is only
-(m.del_H) = (m.Cp.del_T)out

The part that confused me here is what m should I use for these m.del_H and m.Cp.del_T. I obtained the answer stated ealier (121.75 oC) by using the mass for m.del_H is the mass of water produced and the mass for m.Cp.del_H is the mass of the total mass of NaOH+H2SO4 that reacted. Is this correct? If yes, is the temperature I got reasonable? If not, what's my mistake?
 
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