- #1
r_swayze
- 66
- 0
How would you solve a problem such as this?
A Honda and a Porsche race, starting from the same point. The Honda accelerates at a constant 4.00 m/s2; the Porsche at a constant 8.00 m/s2. The Porsche gives the Honda an advantage by letting it start first. The Honda accelerates, and when it is traveling at 23.0 m/s, the Porsche starts. How far do the cars travel from the starting point before the Porsche catches up with the Honda?
All I have is this:
honda v = 4x = 23 m/s
x = 5.75 s
honda position = 2x^2
honda (5.75) = 2(5.75)^2 = 66.125 m
so all I know is when the honda is 66.125 meters the porche starts to go.
what do I next?
A Honda and a Porsche race, starting from the same point. The Honda accelerates at a constant 4.00 m/s2; the Porsche at a constant 8.00 m/s2. The Porsche gives the Honda an advantage by letting it start first. The Honda accelerates, and when it is traveling at 23.0 m/s, the Porsche starts. How far do the cars travel from the starting point before the Porsche catches up with the Honda?
All I have is this:
honda v = 4x = 23 m/s
x = 5.75 s
honda position = 2x^2
honda (5.75) = 2(5.75)^2 = 66.125 m
so all I know is when the honda is 66.125 meters the porche starts to go.
what do I next?