The discussion focuses on converting frequency to energy for a vibrating silicon atom, specifically using the relation E = ħω. The user is attempting to transition from a normalized frequency range of 2 to 80 meV, utilizing the formula ω = 2√(K_i/M), where K_i is given as 10.6 eV/Ų and M is the mass of silicon. There is uncertainty about how to achieve the conversion to reach the desired energy values. The user has successfully calculated a frequency in 1/s using the mass of silicon in meV/c² but is seeking further clarification on completing the conversion. Understanding this relationship is crucial for accurately determining energy levels in silicon atoms.
#1
msimmons
17
0
When considering a vibrating silicon atom.
I'm just not sure how to do the conversion
MeV is mega-electron volts which is equivalent to Joules or energy. So you can't convert frequency to energy.
#3
msimmons
17
0
I know, not directly, but I'm looking for a relation that's something along the lines of E=\hbar\omega but I don't know of any.
Essentially, I'm going from a unitless/normalized frequency of 2 to 80 mevs using \omega=2\sqrt{K_i/M} where K_i is 10.6 eV/\AA^2 and M is the mass of silicon. I should get approximately 80 mevs.. Not sure how I get there. I got to 1/s easily by using the mass of silicon in mevs/c^2 but that's about it
I think it's easist first to watch a short vidio clip
I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way?
The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Do we even know? My understanding of dark energy is that particles come into existence, exert and outward force, then vanish. My problem with that is how, of course, then how does dark energy know to push everything in the same direction? The pressure exerted would be in all directions, even if the space was moving so why isn't stuff pushed all over the sky?
Thanks - rev