How Do You Correctly Calculate Rth in Thevenin Equivalent Circuits?

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Discussion Overview

The discussion revolves around calculating the Thevenin equivalent resistance (Rth) in a circuit with respect to specific terminals. Participants explore various methods and approaches to determine Rth, including the use of node voltage and mesh current techniques, while addressing the implications of shorting and opening sources in the circuit.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant attempts to calculate Rth by removing sources and arrives at a value of 20 kΩ, expressing uncertainty about the cancellation of certain resistors.
  • Another participant suggests that shorting the voltage source results in the 2kΩ and 20kΩ resistors being in parallel.
  • A different participant calculates Rth using a series of parallel combinations, arriving at 12 kΩ and questions the treatment of resistors when opening the current source.
  • One participant clarifies that the current source should not be shorted but replaced with open terminals, prompting a review of Thevenin's theorem.
  • A later reply notes that the current source in the circuit is dependent.

Areas of Agreement / Disagreement

Participants express differing views on how to handle the sources in the circuit and the resulting impact on the resistors. There is no consensus on the correct approach to calculating Rth, and multiple competing methods are presented.

Contextual Notes

Some participants express uncertainty regarding the treatment of specific resistors when sources are shorted or opened, indicating a need for clarity on the definitions and procedures involved in Thevenin equivalent calculations.

Who May Find This Useful

Students and individuals studying circuit analysis, particularly those seeking to understand Thevenin's theorem and its application in determining equivalent resistances in electrical circuits.

orangeincup
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Homework Statement


Determine the Thevenin equivalent with respect to the terminals a,b.

Homework Equations


Rth=Voc/Isc

The Attempt at a Solution


Right now I'm just trying to calculate Rth by removing the sources from the circuit. When I calculated the Rth using the node voltage/mesh current method I calculated it to be 20 kΩ.

So right now my idea is I have to short out the voltage source and open the current source.

I think(?) this means the 2kΩ, 20kΩ, and 5kΩ(maybe not) would be canceled out and the rest of the circuit would be intact.

So I calculated Rth based on the rest...

(40kΩ+10kΩ)||50kΩ=25kΩ

Can someone explain what I did wrong?

I also tried doing
(10kΩ+50kΩ)||20kΩ+5kΩ which gave me an answer of 20kΩ but I do not think I can add the 5kΩ resistor to the 20kΩ resistor in that order.
 

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I think(?) this means the 2kΩ, 20kΩ, and 5kΩ(maybe not) would be canceled out and the rest of the circuit would be intact.
shorting the voltage source means the 2k and 20k resistors are in parallel.
 
(40kΩ+10kΩ)||50kΩ=25kΩ

(25kΩ+5kΩ)||20kΩ=12kΩ

12kΩ||2kΩ=1.74kΩ

Am I suppose to ignore some of the resistors due to shorting the current source? What does opening it do to the 10kΩ or the 40kΩ resistor?

Am I suppose to open the voltage source and short the circuit source or vise versa?
 
It's a dependent current source.
 

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