How Do You Determine the Allowed Radii in a Quantized Angular Momentum Scenario?

AI Thread Summary
The discussion focuses on determining the allowed radii of a charged particle moving in a magnetic field, where the angular momentum is quantized. The relationship between the particle's mass, charge, speed, and the magnetic field is established through the equation r_n = mv/qB, which describes the radius of the circular path. By substituting the quantized angular momentum condition mvr_n = 2nh into this equation, the final expression for the allowed radii is derived as r_n = √(2nh/qB). This approach effectively ties the concepts of magnetism and quantum mechanics together. The solution confirms the correct formulation of the radius in terms of the quantum number n, Planck's constant h, charge q, and magnetic field B.
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Homework Statement



A particle of charge q and a mass m, moving with a constant speed v, perpendicular to a constant magnetic field B, follows a circular path. If in this case the angular momentum about the center of this circle is quantized so that mvr_n = 2nh, determine the allowed radii for the particle in terms of n, h, q, and B for n = 1,2,3,...

Homework Equations



F = qvBsin\vartheta

The Attempt at a Solution



As far as I can tell, this has something to do with relating magnetism to the quantum level. It is easy enough to calculate the radius at a given energy level by solving for r_n. But I do not understand how to relate the charge and the B field to the situation. The best I can come up with is the formula provided... I feel like there is some way it ties into the problem. Help greatly appreciated.
 
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Use the relevant equation you have provided to write Newton's Second Law, F = ma. What is the acceleration for circular motion?
 
\frac{mv^2}{r_n} = qVB sin \vartheta

sin \vartheta = 0 as the angle of the particle with the B field is 90 degrees.

So, simplifying I get,

r_n = \frac{mv}{qB}

How do I tie in this equation with the above?
 
Last edited:
try to use your original equation mvr = 2nh again in the last equation to get red of mv ..
 
I think I see it now.

mv = \frac{2nh}{r_n}

Subbing mv into equation from above r_n = \frac{mv}{qB}

I get

r_n = \frac{2nh}{r_nqB}

A bit more simplification yields r_n = \sqrt{\frac{2nh}{qB}}

Is that correct?
 
well, it seems correct to me since you achieved what is required in the question which was asking to write r in terms of n, h, q, and B ..
 
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