How Do You Determine Time in an RC Circuit for Charge and Current Changes?

  • Thread starter Thread starter wildredhead
  • Start date Start date
  • Tags Tags
    Rc Terms
AI Thread Summary
To determine the time for the charge on a capacitor in an RC circuit to reach 50% of its final value, the equation Q=CV(1-e^-t/RC) is used. The time constant, τ = RC, plays a crucial role in these calculations. For the charge to reach 50%, t can be expressed as t = RC * ln(2). Similarly, to find the time for the initial current to drop to 10% of its initial value, the same time constant is applied, leading to a different calculation involving the exponential decay of current. Understanding these relationships is essential for solving the problem effectively.
wildredhead
Messages
7
Reaction score
0

Homework Statement



The capacitor in an circuit is initially uncharged
In terms of R and C, determine the time required for the charge on the capacitor to rise to 50% of its final value.

In terms of R and C, determine the time required for the initial current to drop to 10% of its initial value

Homework Equations




I know i need to use Q=CV(1-e^-t/RC)
But I don't know how to put it all together.

The Attempt at a Solution

 
Physics news on Phys.org
Hi wildredhead! :smile:

(try using the X2 tag just above the Reply box :wink:)
wildredhead said:
I know i need to use Q=CV(1-e^-t/RC)
But I don't know how to put it all together.

Show us how far you've got, and where you're stuck, and then we'll know how to help! :smile:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top