How Do You Determine Values of p and q in Differential Equation Superposition?

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SUMMARY

The discussion focuses on determining the coefficients p and q in the superposition of solutions for the differential equation y'[t] + 9.7 y[t] = 3 E^(-0.4 t) Cos[t] with initial condition y[0] = 3. The solutions y1[t] and y2[t] are derived from the equations y'[t] + 9.7 y[t] = E^(-0.4 t) Cos[t] and y'[t] + 9.7 y[t] = 0, respectively. By substituting y[t] = p y1[t] + q y2[t] into the original equation, one can derive a solvable equation for p and q.

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Homework Statement



y1[t] solves
y't]+9.7 y[t]=E^(-0.4 t) Cos[t], with y[0]=0,
and y2[t] solves

y'[t]+9.7 y[t]=0, with y[0]=1.

What numbers p and q do you pick to make
y[t]=p y1[t] + q y2[t]
solve
y'[t]+9.7 y[t]=3 E^(-0.4 t) Cos[t], with y[0]=3?

Homework Equations




y1[t] solves
y't]+9.7 y[t]=E^(-0.4 t) Cos[t], with y[0]=0,
and y2[t] solves

y'[t]+9.7 y[t]=0, with y[0]=1.
 
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So we got y(t)=p y_1(t)+qy_2(t).

What you need to do now is to plug this y(t) in you equation y^\prime(t)+9,7y(t)=3e^{- 0,4 t}. You will obtain a nice equation this way which you need to solve...
 
Makes sense. Thanks micromass
 

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