How do you differentiate this?

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Dr. HappyNuke
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Here's the problem:

Differentiate: http://www.webassign.net/www31/symImages/9/b/f70b139b79e8157ad26bf9782128ae.gif

I tried this and somehow came up with 7(x^3/2) - 8(x^1/2). But that is not correct.

How do you do this? I really appreciate your help. Thanks.
 
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I applied the Product Rule and got this :

7.Sqrt[x] + (7x - 8)/(2.Sqrt[x])
 
7(x^3/2) - 8(x^1/2) is just from multiplying out the bracket, you haven't actually differentiated it yet. See if you get the right answer when differentiating what you already have :)
 
omg you're right...I feel so stupid. >< I shouldn't have taken calc over the summer! lol
 
Don't worry, I have moments like that far too often. Good luck!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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