How Do You Find the Critical Point of f(x) = e^x - 5x^2 - ln(x)?

jackchen
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Homework Statement



I'm stuck halfway in my differentiation.

The question is:
Suppose f(x) is the following function when x > 0, find the x-coordinate of the critical point of f(x).

Homework Equations



Equation = f(x) = e^x - 5x^2 - ln(x)

The Attempt at a Solution



I solved for: f'(x) = e^x - 10x - 1/x

From here on, I'm stuck. Help please?
Thank you! =)
 
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Do you know bisection method? Newton's method?
 
I'm afraid I don't. I'm very weak in Calculus, sorry!
 
Do you know how I can solve this?
or where I can find a good explanation?

Thank you! =)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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