How do you find the divergence of a vector field?

andrey21
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I am just curious how you find the divergence of the following vector field





Heres my example

u = xz^(2)i +y(x^(2)-1)j+zx^(2) y^(3)k



Am I right in thinking

U take the derivative with respect to x for first term derivative with respect to y for second term...

giving me z^(2) + (x^(2) -1) +x^(2)y^(3)
 
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You have it correct.
 
Thanks LCKurtz just another question I have bin posed.

does div(uxv)

Mean find the divergence of the dot product of vectors u and v.
 
andrey21 said:
Thanks LCKurtz just another question I have bin posed.

does div(uxv)

Mean find the divergence of the dot product of vectors u and v.

No. That wouldn't make any sense because a dot product gives a scalar and divergence applies to vector fields. What it does mean is first take the cross product of a and b, which gives a vector, then take its divergence.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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