How Do You Find the Y-Coordinate of a Parabola's Vertex?

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To find the y-coordinate of the vertex of the given downward parabola represented by the equation y = -0.0022x^2 + 1.578x, substitute the x-coordinate of the vertex, 179.31815, into the equation. This results in calculating y = -0.0022(179.31815)^2 + 1.578(179.31815). The calculation will yield the y-coordinate of the vertex. The vertex represents the maximum point of the parabola, which is crucial for understanding its properties. This method effectively determines the vertex's position in the context of the arch supporting the bridge.
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Homework Statement

Sorry for such an elementary question, but I'm struggling thru Int Alg. Today's nightmare involves a downward parabola. An arch supporting a bridge has the equation y=-0.0022x^2 + 1.578x + 0. Position of left side parabolic arch is (0,0). Using x = -b/2a, I calculated the symmetrical point of the parabola at (358.6363,0). If this is correct, the vertex x-coordinate is 179.31815. I'm stuck at finding the y coordinate of the vertex. Any help would be greatly appreciated.



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You know that y=-0.0022x^2 + 1.578x. What is y when x = 179.31815?
 
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