How to find the equation of a parabola with the following vertex.

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SUMMARY

The equation of a parabola with a vertex at (-3, -2) that opens downward is derived using the vertex form of a parabola, represented as y = a(x - x0)² + y0. In this case, x0 is -3 and y0 is -2, leading to the equation y = a(x + 3)² - 2, where 'a' must be negative to ensure the parabola opens downward. The initial incorrect equation provided was y = -3x² - 3x - 2, which does not conform to the vertex form.

PREREQUISITES
  • Understanding of the vertex form of a parabola
  • Knowledge of how to manipulate quadratic equations
  • Familiarity with the concept of parabola orientation (opening up or down)
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the vertex form of quadratic equations in detail
  • Learn how to determine the value of 'a' for different orientations of parabolas
  • Practice converting standard form equations to vertex form
  • Explore graphing techniques for parabolas using software tools like Desmos
USEFUL FOR

Students learning algebra, mathematics educators, and anyone interested in mastering the properties and equations of parabolas.

Cobalt
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1. I need to find the equation of a parabola with a vertex of (-3,-2). It has to open down.



2. I understand of hopefully will understand it.



3. My answer was y=-3x Squared -3x-2 Which I found to be wrong.

 
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Welcome to PF!

Hi Cobalt! Welcome to PF! :smile:
Cobalt said:
1. I need to find the equation of a parabola with a vertex of (-3,-2). It has to open down.

My answer was y=-3x Squared -3x-2 Which I found to be wrong.

yes, it goes through (-3,-2) …

but it's -3(x + 0.5)2 + something. :wink:
 
A parabola with vertex at (x0, y0) is given by
y= a(x- x0)2+ y0. If opens downward, then a must be negative.
 

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