How do you isolate this equation ?

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To isolate the equation for time, the equation d = V1(t) - 0.5(a)(t^2) can be rearranged to form a quadratic equation in t. The rearranged form is d - 0.5(a)(t^2) = V1(t), which leads to a standard quadratic equation. This equation can be solved using the quadratic formula, yielding two potential solutions for t. The discussion emphasizes the importance of recognizing the equation's quadratic nature to find the correct time values. Understanding this process is crucial for solving similar physics problems involving motion.
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Homework Statement



I am having trouble isolating this equations for time

d= V1(t) - 0.5 (a) (t2)
2. The attempt at a solution

I get this:

d-0.5(a)(t2) = t
that is all over V1
 
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that's a quadratic equation in t;
it has two solutions for t , given by the "quadratic formula".
 
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