How do you know the order of ligands?

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The discussion focuses on determining the correct order of ligands in the complex triammineaquadihydroxochromium(III) chloride. The transition metal chromium (Cr) is placed first, followed by anionic ligands, which in this case are hydroxide ions (OH). Neutral ligands, such as water (H2O) and ammonia (NH3), should be organized alphabetically by their chemical symbols. The final formula is established as [Cr(OH)2(H2O)(NH3)3]Cl. The conversation highlights the importance of following IUPAC naming conventions for clarity in chemical nomenclature.
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Homework Statement


So i have triammineaquadihydroxochromium(III) chloride and i have to write the formula.

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The Attempt at a Solution


So there's (NH3)3, H2O, (OH)2, Cr and a Cl anion

I know the transition metal goes first, and the charge of the complex is 1+ so it'll be = {Cr - - - ] Cl

But now how do i know what order to put the (NH3)3, H2O, (OH)2? I don't think it has to be alphabetical. If it is alphabetical then this is simple. And it can't just be put the metal, then the neutral ligands then charged ligand because there are two neutral ligands, (NH3)3 and H2O, so which one of those would go first...
 
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so i think i found out how to do it, neutrals should come before charged ligands, and neutrals should be organized alphabetically according to chemical symbol, not name.

So this will be [CrH2O(NH3)3(OH)2]Cl

But I am really not too sure, i see so many complexes that have the metal then a negatively charged ligand then the neutral. Like [CrCl2(H2O)4]
 
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TBH I am not sure what the correct answer ism but the only authoritative source on that will be one of the IUPAC books defining naming rules. Quick googling suggests it is a so called "Red book".
 
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As IUPAC Rule
First is always Cation and then anion
In your example cation is a complex and anion is Cl-
triammineaquadihydroxochromium(III) ...Now here first write the Transition metal (Cr) ,then anionic ligand (2OH-) and then neutral ligand alphabetically (first H2O and then NH3 )
a
So The answer is [Cr(OH)2(H2O)(NH3)3]Cl
 
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