How Do You Measure Heat Energy in Water Exposed to Microwaves or Sunlight?

AI Thread Summary
To determine the heat energy absorbed by water in an insulated cup, one can use the power or power density of the microwave or sunlight source rather than the indirect method involving Planck's constant. The discussion emphasizes calculating the time required for water to boil from 23 degrees Celsius to 100 degrees Celsius, assuming no heat loss. Key factors include the surface area exposed to sunlight and the heat capacity of the water. On a bright day, sunlight provides approximately 1 kW/m² of power, though some energy may be reflected. Accurate calculations depend on these variables to estimate the heating time effectively.
moonman239
Messages
276
Reaction score
0
If I microwave an insulated cup of water or expose it to sunlight, how do I determine the amount of heat energy? Do I use the equation E=hv, where h = Planck's constant and v = the frequency of the microwaves?
 
Science news on Phys.org
This would work if you knew how many photons are absorbed. Though formally feasible, such a method is quite indirect. Normal people would use the power, or the power density, of the light or microwave source to compute the power absorbed and converted into heat.
 
Enthalpy said:
This would work if you knew how many photons are absorbed. Though formally feasible, such a method is quite indirect. Normal people would use the power, or the power density, of the light or microwave source to compute the power absorbed and converted into heat.

Ok.

I leave a cup of water out in the sun. Currently, the temperature of the water is 23 degrees Celsius. Assuming no heat loss, calculate the time the water will take to boil if the boiling point is 100 degrees.
 
Do you know the surface area (as seen from the sun)?
Do you know the heat capacity of your cup of water?

On a bright day, sunlight has a power of about 1 kW/m^2. Some parts will be reflected, but I think you can neglect that.
 
Back
Top