How Do You Solve a Newton's Second Law Problem with a Free Body Diagram?

AI Thread Summary
To solve a Newton's Second Law problem using a Free Body Diagram (FBD), start by identifying the forces acting on the mass, including gravitational force (Fg) and any applied force (F). The net force (Fnet) is calculated using the equation Fnet = mass (m) x acceleration (a). In the discussion, the calculations led to determining the mass as approximately 10.2 kg and the net force as 10.04 N. The final acceleration was confirmed to be 0.98 m/s², with a suggestion to round it to 1.0 m/s² for significant digits.
oMovements
Messages
28
Reaction score
0

Homework Statement


There is an attachment of a FBD, and you have to solve for the following:
Fg=?
Fnet?
Mass=?

The Attempt at a Solution


I know you will have to equate equations, but I don't know how to go about doing this.
I do know that Fg= m x 9.8, I isolated various equations and subbed them into each other and got no answer.
 

Attachments

  • Untitled.jpg
    Untitled.jpg
    4.3 KB · Views: 405
Physics news on Phys.org
Remember that the net force = mass X acceleration.
You have the acceleration, you have the two forces acting on the mass, and mass m.

You are almost there.
 
  • Like
Likes 1 person
barryj said:
Remember that the net force = mass X acceleration.
You have the acceleration, you have the two forces acting on the mass, and mass m.

You are almost there.

Fnet=ma
-Fg+F=ma
-9.8m+110 = m
-10.8m=-110
m=10.2kg

Fnet=-Fg+F
=-9.8m+110
=-9.8(10.2)+110
Fnet=10.04N

a= Fnet/m
a=10.04/10.2
a=0.98 m/s/s

Is this correct?
 
Looks good. However, you might use some more significant digits as the last part, a should be 1.0 as given.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top