How Do You Solve Complex Torque Problems in Physics?

  • Thread starter Thread starter SJustice21
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
The discussion focuses on solving complex torque problems in physics, specifically involving a uniform plank, a horizontal force exerted by a person, and the moment of inertia of a stool-like structure. For the first problem, the key is determining the tipping point based on the normal reaction at the support when the person reaches maximum distance. The second problem involves calculating the horizontal force exerted by a muscle in response to a given force. The third problem emphasizes correctly applying the moment of inertia formula for the rods attached to the disk, suggesting that the moment of inertia is simply three times the mass of each rod multiplied by the square of the radius. Accurate calculations are crucial for solving these torque-related physics problems.
SJustice21
Messages
1
Reaction score
0
The 1st Problem is:
A uniform plank of length 5.9 m and weight 216 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 447 N walk on the overhanging part of the plank before it just begins to tip?
________m


2nd is:
A person exerts a horizontal force of F = 174 N in the test apparatus shown in the drawing. (h = 0.33 m.) Find the horizontal force M that his flexor muscle exerts on his forearm.
Magnitude __________N


3rd is(hardest one):
A solid circular disk has a mass of 1.2 kg and a radius of 0.12 m. Each of three identical thin rods has a mass of 0.13 kg. The rods are attached perpendicularly to the plane of the disk at its outer edge to form a three-legged stool (see the drawing). Find the moment of inertia of the stool with respect to an axis that is perpendicular to the plane of the disk at its center. (Hint: When considering the moment of inertia of each rod, note that all of the mass of each rod is located at the same perpendicular distance from the axis.)____________kg . m2


*Any help will be Appreciated
 
Physics news on Phys.org
Where are the drawings?
 
1st
When the person is at max distance and at the verge of tipping the normal reaction at the support on other side is just zero, balances the torque due to weight of the plank and that of the person.

3rd
The hint is given but I guess still you have taken moment of inertia of the rods wrongly

it will be simply 3 x mR^2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top