- #1
krispiekr3am
- 23
- 0
5x = 1 (mod 13)
13x = 2 (mod 23)
37x = 5 (mod 13)
13x = 2 (mod 23)
37x = 5 (mod 13)
krispiekr3am said:5x = 1 (mod 13)
13x = 2 (mod 23)
37x = 5 (mod 13)
You could use the chinese remainder theorem if you can put it in the appropriate form. For example if you find some k such that 5k = 1 mod 13 (Euclid's algorithm), then the first equation is x = k (mod 13).krispiekr3am said:5x = 1 (mod 13)
13x = 2 (mod 23)
37x = 5 (mod 13)
matt grime said:Are those even compatible?
When there are multiple variables, you need to use a system of equations to solve for X. This means you will have multiple equations with multiple variables, and you will need to use algebraic techniques such as substitution or elimination to solve for X.
The order of operations for solving for X is the same as the order of operations for solving any other equation. This means you should first simplify any parentheses or brackets, then perform multiplication and division from left to right, and finally addition and subtraction from left to right.
To solve for X when there are fractions involved, you will need to find a common denominator and then combine the fractions. Once you have a single fraction, you can use algebraic techniques to isolate X and solve for it.
To check your answer when solving for X, you can plug the value you found for X back into the original equation and see if it satisfies the equation. If both sides of the equation are equal, then your answer is correct.
If you get a negative value for X, it means that your equation has a solution, but it is not a real number. This could happen if the original equation involves square roots, which can result in positive or negative values. You can still check your answer and see if it satisfies the equation.