How Do You Solve Integrals with Complex Bounds?

Dassinia
Messages
141
Reaction score
0
Hello,
I'm studying for the exam and in the previous one there's a question like:

Homework Statement


Find the value of
1/(2*i*pi) ∫ exp(s*u)/s² ds for s from 1-i∞ to 1+i∞

What is the way to solve integrals with complex bounds ? Is it to make a variable change to get real bounds, like here for example s=1+iz and then use residus to solve the integral ?

Thanks
 
Physics news on Phys.org
Dassinia said:
Hello,
I'm studying for the exam and in the previous one there's a question like:

Homework Statement


Find the value of
1/(2*i*pi) ∫ exp(s*u)/s² ds for s from 1-i∞ to 1+i∞

What is the way to solve integrals with complex bounds ? Is it to make a variable change to get real bounds, like here for example s=1+iz and then use residus to solve the integral ?

Thanks

That sounds like a good first step.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top