How Do You Solve Momentum and Elastic Collision Problems in Physics?

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To solve momentum and elastic collision problems, it's essential to apply the conservation of momentum and kinetic energy principles. In the given scenario, the steel ball's velocity changes direction after colliding with the rubber ball, indicating a need to analyze both x and y components of momentum. When considering elastic collisions, the two objects cannot stick together, and the equations derived from conservation laws must account for all variables. The discussion highlights the complexity of solving for unknown velocities, particularly when multiple solutions arise, suggesting the need for careful consideration of the collision dynamics. Understanding these principles is crucial for accurately determining post-collision speeds.
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A steel ball of mass 10kg moves due east at 5.0m/s. It collides with a rubber ball of mass 5.0 kg moving at 10m/s due north. After the collision the steel ball moves at an angle of 60 degrees East of North with a speed of 4.0 m/s.
If the collision were perfectly elastic what would be the speeds of the two balls after the collision?

Where do I start. I know total momentum before = total momentum after. But there seems to be 2 variables. vafter for steel ball and v after for rubber ball.

Can an elastic collision have the 2 objects even stick together?
If so then i got 1.92m/s.
 
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If the collision is elastic the 2 objects won't stisk together.

Try thinking of momentum as a vector. You can use triginometry for the angel, but I don't think it's really necesry.

P.S. don't forget that the mass of the 2 balls is constant.
 
You have two unknowns so you need two equations. Yes, one of the equations is "momentum before= momentum after", conservation of momenum. Since this collision is "elastic", the other is "kinetic energy before= kinetic energy after": conservation of energy.

Momentum is a vector quantity so you will need to consider x and y components separately. Kinetic energy is a "scalar" quantity so you really have 3 equations for 4 unknowns (x and y components of both velocities) but fortunately you are given the angles.
 
I need help on another question
A ball of mass 3.0kg moving at a speed of 3.0ms has a head-on collision with a stationary ball of mass 4.0kg.

If the collision were perfectly elastic what would be the speeds of the two balls after the collision?

I used the momentum before=momentum after equation and the KE before= Ke after equation.

I get weird answers. I get 2 answers. I get the velocity of the 3kg ball at -.42m/s and 3m/s. So what's the answer? If i know the velocity of the of this ball I can find the velocity of the other.
 
krypt0nite said:
I need help on another question
A ball of mass 3.0kg moving at a speed of 3.0ms has a head-on collision with a stationary ball of mass 4.0kg.

If the collision were perfectly elastic what would be the speeds of the two balls after the collision?

I used the momentum before=momentum after equation and the KE before= Ke after equation.

I get weird answers. I get 2 answers. I get the velocity of the 3kg ball at -.42m/s and 3m/s. So what's the answer? If i know the velocity of the of this ball I can find the velocity of the other.
Using only considerations of energy&momentum conservation before and after collision will always yield two sets of possible answers (solutions):
1) There hasn't been any interacting force between the two objects in the collision period.
That is, there wasn't any collision after all.
2) There has been a net momentum transfer (through a non-zero force) during collision.

Your 3m/s possibility is clearly of the trivial 1)-type.
 
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