How Do You Solve Projectile Motion Problems Involving Angles and Heights?

AI Thread Summary
To solve projectile motion problems involving angles and heights, first determine the time of flight by analyzing the vertical motion, considering the initial vertical velocity and the height of the tower. The horizontal distance can be calculated using the horizontal component of the initial velocity and the time of flight obtained in the first step. For the final velocity upon impact, calculate the horizontal component, which remains constant, and the vertical component, which is affected by gravity. Trigonometric functions are essential for breaking down the initial velocity into its components. Understanding these principles allows for accurate predictions of projectile behavior in various scenarios.
TheKovac
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Homework Statement


A object is projected with a velocity of 100 m/s at an elevations 30 degrees from a tower 150m high.

a) Time of flight
b) The horizontal distance from the tower at which the stone strikes that ground.
c) The magnitude and the direction of the velocity of the stone striking the ground.

Homework Equations


x=ut+0.5at^2
Trigonometry
v^2 = u^2 + 2ax

The Attempt at a Solution



a)

=>v=u+at
50.2=100 -10t
t1= 5.02s
t2 = 5.02s
t3=?

Am I on the right track at all?
 

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TheKovac said:

Homework Statement


A object is projected with a velocity of 100 m/s at an elevations 30 degrees from a tower 150m high.

a) Time of flight
b) The horizontal distance from the tower at which the stone strikes that ground.
c) The magnitude and the direction of the velocity of the stone striking the ground.

Homework Equations


x=ut+0.5at^2
Trigonometry
v^2 = u^2 + 2ax

The Attempt at a Solution



a)

=>v=u+at
50.2=100 -10t
t1= 5.02s
t2 = 5.02s
t3=?

Am I on the right track at all?
what are these t1 t2 and t3 ?
If you have the book PHYSICS by Resnic and Haliday please look in it for the solution.
bye
 
You have some help https://www.physicsforums.com/showthread.php?t=227924".

For the (a) part you have vertical shot (y component of the velocity) and then free fall from the height of 150 m at initial velocity of v_{y}=v_{0}sin\alpha.

For the (b) part you need the x component. You have the time from the (a) part, so it's pretty easy.

(c) part is also simple. You need the net velocity (trigonometry). X component doesn't change but the y component is increased by gravity.
 
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