How Do You Solve y(x+2) = 9 to Minimize x+y?

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Homework Statement



Supposed to take the derivative of:

y(x+2) = 9

I think this is one for the chain rule...


Am getting stuck with a fraction with exponent at the bottom and that's a no no that I can't get out of...

The Attempt at a Solution



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I'm confused, what is 'y'? And why do you change to 'f'?
 
You're kind of right (though I don't know why you introduce a function f). Your derivative on line 4 is off by a minus sign; it should read
\frac{dy}{dx}=-\frac{9}{(x+2)^2}

This is the solution: I don't know what you're doing in the next line.
 
Pengwuino said:
I'm confused, what is 'y'? And why do you change to 'f'?

I figured that y and f(x) are the same things just different notation.

The original question is "from all positives numbers X and Y that fulfill y(x+2) = 9, find the two numbers that for them the sum x+y is minimal."

So I thought to take the derivative of y, i.e. f(x) and set it equal to zero. Currently am stuck in the first phase though.

Edit: Oh wait, I did take the derivative successfully, just was off by a minus sign, right? :) Wheepee!
 
cristo said:
You're kind of right (though I don't know why you introduce a function f). Your derivative on line 4 is off by a minus sign; it should read
\frac{dy}{dx}=-\frac{9}{(x+2)^2}

This is the solution: I don't know what you're doing in the next line.

I thought the -9 times the -1 on line 4 give a plus?
 
Femme_physics said:
So I thought to take the derivative of y, i.e. f(x) and set it equal to zero. Currently am stuck in the first phase though.
Don't forget - what is the function that you need to minimize?
 
Femme_physics said:
I thought the -9 times the -1 on line 4 give a plus?
As already noted, you have an extra minus sign. In your work you have
f'(x) = -9(x + 2)-2(-1)
That final (-1) should not be there. Your factor of -9 already includes (-1) from the exponent on x + 2.
 
I think I completely fudged the concept of the question.

diazona said:
Don't forget - what is the function that you need to minimize?

The original question is "from all positives numbers X and Y that fulfill y(x+2) = 9, find the two numbers that for them the sum x+y is minimal."

That final (-1) should not be there.

Ah...thanks.. I thought that's how you use the chainrule, but you're just suppose to take the derivative of the whole thing I see. My bad.So now that I have the right derivative, but apparently my direction of how to solve the question is off because no real values = 0. I'll try to figure it out, I appreciate all the corrections with my basic calculus.
 
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