How do you write equations in a single sine function?

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SUMMARY

The discussion focuses on converting the function y = -3sin(x) + 2cos(x) into a single sine function. The equivalent form is expressed as y = Rcos(ωx + φ), where R is calculated using the formula R = sqrt(A^2 + B^2) and φ is determined by φ = tan^-1(A/B). For the given function, A is -3 and B is 2, leading to R = sqrt((-3)^2 + (2)^2) = sqrt(13) and φ = tan^-1(-3/2). This transformation simplifies the analysis of the function's characteristics.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Familiarity with the concepts of amplitude, period, and phase shift
  • Knowledge of the Pythagorean theorem for calculating R
  • Basic skills in inverse trigonometric functions for determining φ
NEXT STEPS
  • Study the derivation of the formula y = Rcos(ωx + φ) in detail
  • Learn about the properties of sine and cosine functions in transformations
  • Explore applications of phase shifts in wave functions
  • Investigate the graphical representation of combined sine and cosine functions
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Students and educators in mathematics, particularly those studying trigonometry, as well as engineers and physicists working with wave functions and oscillatory systems.

princiebebe57
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What would the Domain, Range, Amplitude, Period, Phase shift be for y=-3sin(x)+2cos(x)?

How do you write it as a single sine function equivalent to it? :confused:
 
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When you have a function of
y=Asinωx+Bcosωx

that will be equivalent to:
y=Rcos(ωx+φ)

where R=sqrt(A^2+B^2) and φ=tan^-1 (A/B)
 

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