How does 1,4 H elimination work in butene?

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The discussion revolves around the conversion of 2-cis-butene to 1,3-butadiene through a reaction termed "1,4-H elimination." The nature of this reaction is questioned, particularly whether it requires a radical species or if it occurs via auto-elimination. There is a suggestion that this process may resemble a pericyclic reaction, akin to a retro-Diels-Alder mechanism, especially given the terms "unimolecular" and "symmetry-forbidden" mentioned in a referenced paper. The participant expresses a desire to understand the reaction mechanism better and seeks guidance on changing the discussion title to reflect the focus on 1,4-H elimination in butene.
dRic2
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Hi, I've read that 2-cis-butene gives 1,3-butadiene by "1,4-H elimination". I don't really understand what kind of reaction it is. Does it involve the presence of a radical specie or is it an "auto-elimination"? How does it work?

Thanks !EDIT: How can I change the title to "1,4 H elimination in butene" ?
 
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Conventional wisdom (I.e., my intuition) leads me to believe that—at least in its uncatalyzed incarnation—it’s a pericyclic reaction similar to a retro-Diels Alder. I can’t see the full paper here right at the moment:
https://onlinelibrary.wiley.com/doi/abs/10.1002/kin.550050608
but the words “unimolecular” and “symmetry-forbidden” lead me to believe my intuition is right.
 
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I can't read the full paper, but thanks for the link and the suggestions! :)
 
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