How Does a Charge Affect a Uniform Electric Field?

AI Thread Summary
A charged particle with +7.88 μC affects the uniform electric field of 300 N/C, creating a point along the x-axis where the electric field strength is zero. This occurs because the presence of the charge alters the field configuration, despite the initial uniform field. The problem assumes the charge is significant enough to influence the field, unlike typical scenarios where the charge is negligible. The fixed position of the charge indicates that the analysis focuses on the resultant field rather than the charge's movement. Understanding this interaction is crucial for solving the problem accurately.
r_swayze
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A particle with charge +7.88 μC is placed at the fixed position x = 3.00 m in an electric field of uniform strength 300 N/C, directed in the positive x direction. Find the position on the x-axis where the electric field strength of the resulting configuration is zero.


I don't understand this problem. I thought if the electric field is of uniform strength, then the strength would be 300N/C throughout the field. How can the field strength be zero?
 
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r_swayze said:
A particle with charge +7.88 μC is placed at the fixed position x = 3.00 m in an electric field of uniform strength 300 N/C, directed in the positive x direction. Find the position on the x-axis where the electric field strength of the resulting configuration is zero.


I don't understand this problem. I thought if the electric field is of uniform strength, then the strength would be 300N/C throughout the field. How can the field strength be zero?

The charged particle would change the uniform field. In many questions of this nature, they give you a charged particle that is small enough that it does not effect the uniform field in any signficant manner and then asks you a question about what happens to the particle.

In your problem, I assume the charged particle is having a consequential effect on the uniform field if there is a place in this space where the field strength is zero. Also it says the charged particle is at a fixed position, meaning they don't want it to "react" to the uniform field.
 
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