How Does a Phase Difference Affect Amplitude in Co-Directional Waves?

  • Thread starter Thread starter dnoi
  • Start date Start date
  • Tags Tags
    Direction Waves
AI Thread Summary
The discussion focuses on determining the phase difference between two co-directional waves based on their amplitudes. It is established that if the combined amplitude of the waves is 1.5 times greater than the individual amplitudes, the phase difference can be expressed as delta(phi) = 2 arccos(3/4). The user attempts to derive this by adding the wave equations and substituting the combined amplitude into the equation. Clarifications are made regarding the algebraic steps, specifically the presence of 'a' in the right-hand side of the equation. The conversation emphasizes the importance of careful algebraic manipulation to arrive at the correct phase difference.
dnoi
Messages
5
Reaction score
0

Homework Statement



Two waves traveling in the same direction are identical except for a phase difference. Show that if the amplitude of the sum of the waves is 1.5 times larger than the amplitude of the individual waves, then the phase difference must be

delta(phi) = 2 arccos (3/4)
 
Physics news on Phys.org
Let y1 and y2 be the displacements at a certain point due to the two waves. If the phase diff is 'b', then,

y1 = a*sin(wt),
y2 = a*sin(wt + b).

The rest is algebraic. (Hint: add the two eqns.)
 
thanks!

now i tried...

a*sin(wt)+a*sin(wt+b) = 2sin(wt+b/2)cos(b/2)

substituted 1.5a for 2cos(b/2)

a*sin(wt)+a*sin(wt+b) = (3/2)a*sin(wt+b/2)

is this the right way to go? or maybe i just made some algebraic mistakes
 
dnoi said:
thanks!
a*sin(wt)+a*sin(wt+b) = 2sin(wt+b/2)cos(b/2)
Where is the 'a' on the RHS?

substituted 1.5a for 2cos(b/2)
...for 2*a*cos(b/2)...OK?
 
oh yes. thank you.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top