How Does a Phase Difference Affect Amplitude in Co-Directional Waves?

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Homework Help Overview

The discussion revolves around the effects of phase difference on the amplitude of two co-directional waves that are otherwise identical. The original poster presents a problem involving the mathematical relationship between the amplitudes of the individual waves and their resultant amplitude when combined.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the algebraic addition of wave functions and question the correctness of their manipulations. There is a focus on the implications of substituting values into the equations derived from the wave functions.

Discussion Status

Participants are actively engaging with the mathematical expressions and checking each other's work. There is a collaborative effort to clarify the algebra involved, with some guidance provided on ensuring the correct representation of terms in the equations.

Contextual Notes

There is an assumption that the phase difference and the amplitudes are correctly defined, but the discussion reveals potential confusion regarding the algebraic steps taken to reach the conclusion about the phase difference.

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Homework Statement



Two waves traveling in the same direction are identical except for a phase difference. Show that if the amplitude of the sum of the waves is 1.5 times larger than the amplitude of the individual waves, then the phase difference must be

delta(phi) = 2 arccos (3/4)
 
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Let y1 and y2 be the displacements at a certain point due to the two waves. If the phase diff is 'b', then,

y1 = a*sin(wt),
y2 = a*sin(wt + b).

The rest is algebraic. (Hint: add the two eqns.)
 
thanks!

now i tried...

a*sin(wt)+a*sin(wt+b) = 2sin(wt+b/2)cos(b/2)

substituted 1.5a for 2cos(b/2)

a*sin(wt)+a*sin(wt+b) = (3/2)a*sin(wt+b/2)

is this the right way to go? or maybe i just made some algebraic mistakes
 
dnoi said:
thanks!
a*sin(wt)+a*sin(wt+b) = 2sin(wt+b/2)cos(b/2)
Where is the 'a' on the RHS?

substituted 1.5a for 2cos(b/2)
...for 2*a*cos(b/2)...OK?
 
oh yes. thank you.
 

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