How Does Absorptivity Affect Heat Radiation in Small Temperature Differences?

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The discussion focuses on deriving the rate of heat loss by radiation for a small body in an evacuated enclosure when the temperature difference between the body and the walls is minimal. The formula presented, dQ/dt=4(θ0)^3*Aaσ(θ-θ0), incorporates the area, absorptivity, and Stefan's law. Participants express confusion about differentiating the equation and the role of the constant σ. The key takeaway is that σ remains constant during the differentiation process. Understanding this relationship is crucial for solving the problem accurately.
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Homework Statement



A small body at temperature θ is suspended in an evacuated enclosure with walls at uniform temperature θ0.If (θ-θ0) is small show that the the rate at which the body loses heat bt radiation is given by

dQ/dt=4(θ0)^3*Aaσ(θ-θ0)
where A is the area and a is the sbsortivity of the body.

Homework Equations


The Attempt at a Solution



We should use the Stefan's law:Q=σ[θ^4-(θ0)^4]
the differentiation may be carried out...But I do not understand how to replace σ
 
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\sigma is a constant. You don't replace it with anything. :confused:
 
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