How does air restistance affect a projectile?

  • Thread starter Thread starter lindsey0307
  • Start date Start date
  • Tags Tags
    Air Projectile
AI Thread Summary
Air resistance significantly impacts the trajectory of a projectile, altering the optimal launch angle for maximum distance and hang time. While a 45° angle is ideal in a vacuum, the presence of air resistance typically necessitates a lower launch angle to counteract drag effects. This adjustment helps maintain a balance between vertical and horizontal motion, enhancing overall performance. The discussion highlights the complexity of projectile motion in real-world conditions, emphasizing the need for adjustments based on environmental factors. Understanding these dynamics is crucial for accurate projectile trajectory predictions.
lindsey0307
Messages
6
Reaction score
0
For maximum hang time & distance (with no air resistance) a projectile should be launched at an angle of 45°. However, when air resistance is present, how does this affect the angle at which the projectile is launched at (to achieve maximum hang time and distance)?

I would think that the projectile would need to be launched at an angle less than 45° since air resistance affects the horizontal distance, but I don't believe I'm correct.

Thanks!
 
Physics news on Phys.org
See pages C7, C8, and C9 in,

http://www.hnsa.org/doc/firecontrol/partc.htm

The rest of the booklet is an interesting read.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top