How Does an Electron Move in a Magnetic Field Within a Cloud Chamber?

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An electron moving in a magnetic field within a cloud chamber will describe a helical path if its velocity is not perpendicular to the field. The equation F = q(v x B) indicates that the velocity component contributing to the force is only the one perpendicular to the magnetic field. The parallel component of the electron's velocity remains constant and does not affect the force exerted by the magnetic field. The discussion clarifies that while the path is helical, it is important to distinguish it from a spiral. Understanding these dynamics is crucial for analyzing particle motion in magnetic fields.
DiamondGeezer
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An electron enters a cloud chamber which has a magnetic field B but the path of the electron is not perpendicular to the magnetic field. I understand that the electron path will describe a spiral.

Does the v in the equation F = q(v x B) refer to the component of the electron's velocity which is perpendicular to the B field? Can I assume that an electron's velocity parallel to the B field remains constant and is unaffected by the B field?
 
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The \vec v in that equation is the vector velocity of the electron, including all three (x, y, z) components in general. However, you're correct that the component of \vec v parallel to \vec B does not contribute to \vec F. So if, for example, \vec B is in the z-direction (i.e. B_x = B_y = 0), then it doesn't matter what v_z is, as far as \vec F is concerned:

F_x = q (v_y B_z - v_z B_y)

F_y = q (v_z B_x - v_x B_z)

F_z = q (v_x B_y - v_y B_x)
 
Thank you. That completely answers my question
 
But it is a helix, not a spiral.
 
clem said:
But it is a helix, not a spiral.

Correct.
 
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