How Does an Inductor's DC Behavior Affect Circuit Current Buildup?

AI Thread Summary
The discussion revolves around calculating the maximum current (I_max) in an RL circuit with a resistor of 34.2 Ω, an inductor of 152 mH, and a battery voltage of 33.7 V. The equation I=I_max(1-e^(-t/T)) is used, where T is the time constant calculated as T=L/R. Participants emphasize that I_max represents the steady-state current when the inductor no longer influences the circuit. The voltage of the battery is relevant for determining I_max, as it ultimately dictates the maximum current in the circuit once the inductor's effect has dissipated. Understanding these relationships is crucial for solving the problem effectively.
strawberrysk8
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Homework Statement



Assume that resistor R has a resistance of 34.2 Ω, inductor L has an inductance of 152 mH (milli-Henry), and the battery has a voltage of 33.7 V. Also assume that the circuit elements are ideal.

If the switch S is closed suddenly, the time for the current to attain a value of 82.1 mA is...

Homework Equations



I=I_max(1-e^(-t/T))
T=L/R

The Attempt at a Solution



I need help finding I_max.

82.1 mA=I_max(1-e^(-t/(152/34.2)))

Why do they give me V?
 
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Hi strawberrysk8,

strawberrysk8 said:

Homework Statement



Assume that resistor R has a resistance of 34.2 Ω, inductor L has an inductance of 152 mH (milli-Henry), and the battery has a voltage of 33.7 V. Also assume that the circuit elements are ideal.

If the switch S is closed suddenly, the time for the current to attain a value of 82.1 mA is...

Homework Equations



I=I_max(1-e^(-t/T))
T=L/R

The Attempt at a Solution



I need help finding I_max.

82.1 mA=I_max(1-e^(-t/(152/34.2)))

Why do they give me V?

I_max is the current in the circuit after the current has stopped changing (reached its final value). At that point, the inductor is not affecting the circuit (has no voltage drop across it). So how can you find I_max?
 
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