How Does Centripetal Force Affect Roller Coaster Dynamics?

AI Thread Summary
Centripetal force plays a crucial role in roller coaster dynamics, particularly at points of high speed and elevation. At point A, with a speed of 20.0 m/s, the centripetal acceleration is calculated to be 40 m/s², impacting the force exerted by the track on the vehicle. A free body diagram is essential for visualizing the forces acting on the roller coaster, especially at the top of loops where gravitational force must counteract the required centripetal force. The discussion also highlights the importance of determining the maximum speed at point B to ensure gravity can keep the vehicle on the track. Understanding these dynamics is vital for safe roller coaster design and operation.
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A roller-caster vechicle has a mass of 500 kg when fully loaded with passengers (Fig p7.28) (a) If the vechile has a speed of 20.0 m/s at point A, what is the force of the track on the vehicle at this point? (b) What is the maximum speed the vehicle can have at point B in order for gravity to hold it on the track?

a) a_{c} = \frac{v^2}{r} = 40 m/s^2
 
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dontcare said:
A roller-caster vechicle has a mass of 500 kg when fully loaded with passengers (Fig p7.28) (a) If the vechile has a speed of 20.0 m/s at point A, what is the force of the track on the vehicle at this point? (b) What is the maximum speed the vehicle can have at point B in order for gravity to hold it on the track?

a) a_{c} = \frac{v^2}{r} = 40 m/s^2

Draw a free body diagram. Identify all the forces. The acceleration will be toward the center of the circle (where is the object here? I am assuming that it`s at the very top of a loop? In that case you would have a_y = - v^2/R). Then apply Newton`s second law.
 
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