How Does Charge Placement Affect Electric Potential and Potential Energy?

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The discussion focuses on calculating the electric potential and potential energy involving two point charges of 2.09 micro Coulombs positioned on the x-axis and a third charge of -3.08 micro Coulombs on the y-axis. Participants are encouraged to determine the electric potential at a specific point on the y-axis and to calculate the potential energy of the third charge. The importance of showing attempted work for better assistance is emphasized, as it helps others understand the challenges faced. Additionally, the need for a diagram to visualize the charge placements and their respective distances is highlighted. Overall, the thread seeks clarity on applying Coulomb's Law to solve the problem effectively.
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This question is similar to the one that I posted previously:

Two point charges each of magnitude 2.09 micro Coulombs, are located on the x-axis. One is at x=1.38 m and the other is at x=-1.38 m.

a) Determine the electric potential on the y-axis at y=0.511 m.

b) Calculate the electric potential energy of a third charge, of -3.08 micro Coulombs, placed on the y-axis at y=0.511 m.

I used the same approach for this question as I did for the other question that I posted, i.e. using the summation of Coulomb's Law and various other creative yet ineffective approaches. Any help would be greatly appreciated. Thanks!
 
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Once again, draw a diagram of where the three charges are. This time, you'll find that they are all on either the x- or y-axes and form right triangles. What are the distances of the two charges on the x-axis from the third one on the y-axis? (That is, what do you use to find out?)

It would also be a good idea when you ask for help on this Forum to show some work you attempted. It's hard to tell you why something you tried didn't work if we can't see it...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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