How Does Constant Power Affect Object Motion Compared to Constant Force?

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The discussion focuses on comparing the motion of two objects, A and B, both with mass m, where A is pushed with a constant force and B with a constant power. The participants derive equations for the time taken by each object to travel a distance s, with A's time expressed as t = 2s/3v. For object B, the challenge lies in relating its time to the same variables while accounting for constant power, leading to the equation s = 1/3 (8Pt^3/9m)^(1/2). The main goal is to eliminate the variables P and m to find the ratio of the time taken by both objects. The discussion emphasizes the need to express both equations in terms of s and v for comparison.
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Homework Statement


Object A of mass m is pushed with a constant force, another object B of the same mass is pushed with a force that does work at constant rate. Velocity of both objects increase from v to 2v and they move a distance of s. Find the ratio of the time taken by objects A and B to move the distance s


Homework Equations





The Attempt at a Solution


Firstly, for object A
s = 1/2(v + 2v)t
t = 2s/3v

Object B has constant power, so
change in energy = work done = 3/2 mv2
3/2 mv2 = Pt
v = (2Pt/3m)1/2
integrating this term, i get
s = 1/3 (8Pt3/9m)1/2

But how do i eliminate m and p?
 
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gaobo9109 said:
But how do i eliminate m and p?

Hi gaobo9109! :smile:

You really only have two unknowns, t and P/m, in your last two equations. :wink:
 
but time taken for Object A to travel distance s is given by the equation t = 2s/3v. So my second equation for t should also be expressed in term of s and v so that the two equation can be divided to find the ratio. However, I have P and m in the equation instead. How can I express the second equation in term of s and v?
 
Eliminate P/m from these two equations …
gaobo9109 said:
Object B has constant power, so

3/2 mv2 = Pt

s = 1/3 (8Pt3/9m)1/2
 
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