How Does Copper Wire Shape Affect Magnetic Flux Density?

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic flux density at the center of a square loop made from a 1mm-diameter copper wire with a side length of 4cm, placed in a time-varying magnetic field described by \vec{B}=1t\hat{z} Wb/m². The induced current in the loop is determined to be 0.456 A. The magnetic field H is directed in the -z direction, and the relationship B=4μ₀H is established. The net magnetic field at the center of the loop is calculated by considering the contributions from each segment of the square loop, in accordance with Lenz's law.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with Lenz's law
  • Knowledge of magnetic field calculations
  • Basic concepts of current and magnetic flux density
NEXT STEPS
  • Study the application of Lenz's law in various electromagnetic scenarios
  • Learn about the Biot-Savart law for calculating magnetic fields from current-carrying conductors
  • Explore the relationship between current, magnetic field strength, and induced electromotive force (EMF)
  • Investigate the effects of wire shape on magnetic field distribution
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the principles of electromagnetism and magnetic field calculations.

ryukyu
Messages
19
Reaction score
0
A 1mm-diameter copper wire is shaped into a square loop of side = 4cm. It is placed in a plane normal to a magnetic field increasing with time as [tex]\vec{B}[/tex]=1t[tex]\hat{z}[/tex]Wb/m2. Calculate the magnetic flux density at the center of the loop.


I found that the magnitude of the induced current is 0.456 A
















The Attempt at a Solution



I know that H will be in -z direction

B=4[tex]\mu[/tex]0H

H=?
 
Physics news on Phys.org
You have found the current in the square. Now find the field at the center of the loop due to each segment of the square. According to Lenz's law this field must be in opposite direction to the applied field. Hence find the net field.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
1K