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Homework Statement
A dust cobweb is drawn from an initial vertical position toward a nearby wall by an electrostatic force. Assume the cobweb to be like a single dust ball of mass 2.0 x 10-7g suspended on a massless string of length 0.42 m connected a horizontal distance of 0.35 m from the wall, as shown below. The tethered dust ball is drawn to the wall by another similar dust ball of opposite charge, -q = -3.0 x 10-6C, as shown.
a) Draw a free-body diagram for the tethered dust ball in its final resting position.
b) Transfer the force information from the free-body diagram to a triangle. (I think they mean a component triangle)
c) What is the final charge on the cobweb?
Homework Equations
Fe = \frac{Kq_{1}q_{2}}{d^{2}}
where Fe is the electric force between two objects
K is Coulomb's constant (9.0 x 109 Nm2/C2)
q1 is object 1's electric charge
q2 is object 2's electric charge
d is the distance between centers of charged objects
The Attempt at a Solution
a) just draw the Normal Force, Force of Gravity, and the Electric force?
b)unsure, but i could figure this out alone
c) Would I just solve for the distance between the two dust balls and then sub that into the equation above, using +q for q1 and -q for q2 and 9.0 x 109 for K?
edit: bah, nevermind that failed. need help for c)
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