Suppose there are two planets A and B, each stationary relative to the other at distance x. Now an observer travels from planet A to B. He sees that the distance between them has shortened. If the clocks on the two planets are synchronised, then with the help of a Minkowski diagram, it could be understood that during the start of the journey, the observer observes the clock on planet B to lag behind the clock on planet A by vl/c2, where l is the contracted length.Now the observer reaches planet B, decelerates instantly to a complete stop and observes that planet A jumps back to distance x. Just before deceleration, he sees that the clock on planet A shows time t/γ, where t is the time on his clock. What happens after the deceleration? Does the time on clock A also jump to t or does it remain t/γ? And does the time on clock B, on the planet where he has landed remain (t-vx/c2)/γ or does it jump forward to t?