How Does Elevator Acceleration Affect Scale Readings?

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The discussion focuses on how elevator acceleration impacts scale readings, using a scenario with a 600 N student in an 814 kg elevator. When the elevator accelerates, the scale reads 464 N, prompting calculations to determine the elevator's acceleration. The correct approach involves using the force equation F = ma, where the difference in weight readings indicates the force due to acceleration. The calculations reveal an acceleration of approximately 0.167 m/s². Participants emphasize the importance of understanding the forces involved without complicating the problem with unnecessary variables.
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1. A 600 N physics student stands on a bathroom scale in an 814 kg (including the student) elevator that is supported by a cable. As the elevator starts moving, the scale reads 464 N .
1) Find the magnitude of the acceleration of the elevator.

2.F=ma ?

3.I tried to separate into y and x equations and find the values but it didn't work.
 
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welcome to pf!

hi chs60815! welcome to pf! :wink:
chs60815 said:
… 2.F=ma ?

3.I tried to separate into y and x equations and find the values but it didn't work.

x ?? which way is this elevator going?? :confused:

F = ma should do it …

show us your full calculations, and then we'll see what went wrong! :smile:
 
there is no need for x.
For the question you need to be clear on one thing. The scale just shows the amount of force you give it while standing.
 
No x-axis interactions are happening.
Answer: 600N-X(force caused by elevator)=464N
x=136N=ma
136N/814kg=.167m/s^2
 
mattwoerd said:
No x-axis interactions are happening.
Answer: 600N-X(force caused by elevator)=464N
x=136N=ma
136N/814kg=.167m/s^2

Hey mattwoerd,
It seems you are new to PF. I should tell you something- you are not supposed to solve the whole question in the post. You should only give hints or clear doubts. Read PF rules.
 

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