How Does Elevator Motion Affect the Tension in a Suspended Lamp's Wire?

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    Elevator Lamp
AI Thread Summary
The discussion focuses on calculating the tension in a wire supporting a 3.0-kg lamp in various elevator motion scenarios. For an elevator moving downward at a constant speed of 6.0 m/s, the tension is 29.4 N. When the elevator moves upward at 6.0 m/s and decelerates at 2.0 m/s², the tension increases to 35.4 N. Conversely, if the elevator moves downward at 6.0 m/s while decelerating at 2.0 m/s², the tension decreases to 23.4 N. Participants emphasize the importance of free body diagrams and correctly identifying the direction of acceleration to resolve the tension calculations accurately.
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Homework Statement



A 3.0-kg lamp is suspended by a wire from the ceiling of an elevator. What can you conclude about the
tension in the wire under each of the following circumstances? (Give a numerical result, or a range of possible
numerical results, or if you can’t conclude anything about the tension in the wire, say so explicitly. Justify your
response in each case.)

a. The elevator is moving downward with a constant speed of 6.0 m/s.

b. The elevator is moving upward with speed of 6.0 m/s, and slowing down at a rate of 2.0 m/s/s.

c. The elevator is moving downward with speed of 6.0 m/s, and slowing down at a rate of 2.0 m/s/s. (3 pts)

Homework Equations



F=ma

The Attempt at a Solution



a: ma=Tension-mg
(3kg)(0m/s2)=Tension-(3kg)g
Tension=29.4N

b: ma=Tension-mg
(3kg)(2m/s2)=Tension-(3kg)g
Tension=35.4N

c: ma=Tension-mg
(3kg)(-2m/s2)=Tension-(3kg)g
Tension=23.4N

I'm not sure if I even did this right please check it out!
 
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a looks good, but you got b and c reversed. Draw a FBD, note the direction of the acceleration, and examine the direction of the forces and net forces more closely.
 
Oh yes I got mixed up...Thank you
 
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